CAT
Exam
Numerical Ability
Permutation and Combination
if all the possible words using the letters of the word "DRAW" are formed without repetition and arranged in alphabetical order, what will be the position of the word "WARD"
Read Solution (Total 3)
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- No. of letters in the word "DRAW" = 4
Total no. of words formed can be => 4! = 24
Alphabetical order of DRAW => ADRW
Words Starting with "A" => (A)--- = 3! = 6
Words starting with "D" => (D)--- = 3! = 6
Words starting with "R" => (R)--- = 3! = 6
So 6+6+6 = 18
19th word ll start with "W"
19th word => WADR
20th word => WARD
So "WARD" is present in the 20th position...
Ans : 20 - 10 years agoHelpfull: Yes(9) No(0)
- It should be 20th position out of total 24 positions.
We've DRAW as 4 letters...
Now alphabetically:
Total words starting with A:
A _ _ _ = 1 x 3 x 2 x 1 = 6 words are possible starting with A.
Now next turn comes for D :
D _ _ _ = 1 x 3 x 2 x 1 = 6 words are possible starting with D
Next is R :
R _ _ _ = 1 x 3 x 2 x 1 = 6 words are possible starting with R
We need to find for WARD...All the above possible words are definitely positioned above our desired word WARD:
Now lets take for words starting with W :
After letter W we have A which should only come alphabetically.
W A D R should be the next letter..whose position should be 19th as 18 are already above it.
And next is WARD(Desired word)... Hence its position should be 20. - 10 years agoHelpfull: Yes(3) No(0)
- 19. words starting with A 6
" " " D 6
" " " R 6 - 10 years agoHelpfull: Yes(0) No(2)
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