Two years ago ,a man's age was 3 times the sqr of his son's age.In 3 yrs ,his age will be 4 times his son's age.find the present age.

• man = x , son = y
  
  (x-2)= 3(y-3)^2 ------ 1
  
  (x+3)= 4(y+3) ----- 2
  
  solving 1 & 2
  y = 5, y= 1/3(neglect)
  x = 29
• 9 years agoHelpfull: Yes(15) No(3)
• let two year ago son age is x then father age is 3x^2
  in 3 years (means 3 years after from present year) = 3+2 = 5 years
  according to question
  4(x+5)=3(x^2)+5
  we get x=3
  means 2 year ago son age is 3 then present age of father is 3x^2+2
  3*9+2=29
• 9 years agoHelpfull: Yes(3) No(0)
• yes its y-2 for 2 yrs back
• 9 years agoHelpfull: Yes(1) No(0)
• Two Years Ago,Let father's age be x and son's age be y.
  then we have
  x= 3(y^2)------i)
  After 5 years (two years ago+ in three Years)
  x+5= 4(y+5)----ii)
  Putting ii) in i) and Solving We get, y= -5/3 (neglect) or y= , Thus x= 27
  Thus Father's present age will be x+2 i.e. 27+2=29 and Son's age is (y+2)= 5.
• 9 years agoHelpfull: Yes(1) No(0)
• man=x , son=y
  
  (x-2)=3(y-2)^2
  
  (x+3)=4(y+3)
  
  by solving above 2 equ
  y=5, x=29
  
• 9 years agoHelpfull: Yes(1) No(1)
• hey its y-2 na? 2 yrs bak...pls respond fr ds
• 9 years agoHelpfull: Yes(0) No(0)
• son age is 5yrs & man age is 29yrs
• 9 years agoHelpfull: Yes(0) No(0)