In a certain college 40 % of the senior class student is taking physics .30 % is taking calculus and 10% is taking both.if 40 students are enrolled in the senior class .how many student are taking neither phy nor cal.

• total 40 students
  phy = 16
  cal = 12
  phy & cal both = 4
  either phy or cal = 16 + 12 - 4 = 24
  
  neither phy nor cal = total - either phy or cal = (40-24) = 16
• 10 years agoHelpfull: Yes(24) No(0)
• total % of students taking phy and cal=40%+30%=70%
  % of students having both sub=10%
  70-10=60%
  total students having neither having phy nor cal=100-60=40%
  req no of students=40/100*40=16
• 10 years agoHelpfull: Yes(1) No(0)
• TOTAL STUDENTS 40
  PHY 40% = 16
  CAL 30% = 12
  PHY & CAL BOTH 10% = 4
  100-40
  100%-40%-30%-80%=20%
  NEITHER PHY NOT CAL 20%= 8
• 6 years agoHelpfull: Yes(0) No(0)
• total students ==40 in class
  the people who took physics are 40% of 40 ==16
  the people who took calculus are 30% of 40==12
  the people who took both are ===10% of 40 ==4
  n(pUc)=n(p)+n(c)-n(p∩c)
  =16+12-4
  =24
  n(u)-n(pUc)==40-24==16
  i.e the students are taking neither physics and cal==16
• 3 years agoHelpfull: Yes(0) No(0)