Consider two trains A and B in stations I and II respectively with a distance of 150Km between them. A travels at a speed of 60 Km/hour and B travels at a speed of 100 km/hr towards each other in parallel tracks. A has started with a delay of 6 minutes compared to that of B. Find the distance at which the two trains will meet when measured from station II.

• 97.5 Km from station II.
  
  The distance between the trains = 150
  
  For the first six minutes, when A is at rest, the distance covered by B from station II = Speed of B in Kmph X Time in hours = 100 X 6/60 = 10 Km. -> eq 1
  
  After six minutes, the distance between two trains = 150 - 10 = 140 Km.
  
  From now on, relative speed of B with respect to A = Speed of B + Speed of A = 160 Kmph.
  
  Time when B will cross A = Distance between B and A / Relative speed of B with respect to A
  = 140/160 = 7/8 hours.
  
  In 7/8 hours distance covered by B = Speed of B in Kmph X Time in hours = 100 X 7/8
  = 87.5 Km. -> eq 2
  
  Adding values of eq 1 and eq 2 we will get the answer which is 97.5 Km from station II.
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