how many number of numbers can by formed by using the digits 1,2,3,4 and 5 which are divisible by 6?

• 3 digit numbers formed using 1,2,3,4,5 divisible by 6
  
  unit digit should be 2/4
  no. can be XY2 & XY4
  
  X+Y+2 = 6,9 & X+Y+4 = 9,12
  X+Y = 4,7 & X+Y = 5,8
  (X,Y)= (1,3),(3,1),(2,5),(5,2) &
  (X,Y)= (2,3),(3,2),(3,5),(5,3)
  
  total 8 numbers without repetition.
• 9 years agoHelpfull: Yes(46) No(21)
• For 1 digit=0
  for 2 digit=4
  for 3 digit=8
  for 4 digit=12
  for 5 digit=48
  total=72
  
• 9 years agoHelpfull: Yes(36) No(1)
• divisible by 6 means ->should be divisible by 2 and 3.
  1) for 2 , the unit place should have even number ,thus 4!=24
  2) for 3, the sum is 18 means divisible by 3 ,thus 4!=24
  thus 24+24=48.
  
• 9 years agoHelpfull: Yes(9) No(5)
• HOW MANY 3 DIGIT NUMBERS
  
• 9 years agoHelpfull: Yes(4) No(1)
• 
  first of all
  single digit no . =0
  2 digit no(12,24,42,54)=4
  3 digit no=12
  4digit no=24
  5digit no=24
  
  totalno=64
• 9 years agoHelpfull: Yes(4) No(6)
• Qn : How many three digit numbers can be formed (without repetition) by using the digits 1,2,3,4 and 5 which are divisible by 6?
  Ans : For 6, both 2 & 3 division rules should be satisfied.
  So Unit digit should be 2 or 4
  Numbers can be XY2 & XY4
  X+Y+2 & X+Y+4 should be divisible by 3.
  (X,Y,2)= (1,3,2),(3,1,2),(3,4,2),(4,3,2)
  (X,Y,4)= (2,3,4),(3,2,4),(3,5,4),(5,3,4)
  So 8 numbers are possible.
• 8 years agoHelpfull: Yes(4) No(0)
• rakesh how is it possible...u told that with out repetition..bt u consider,( 5,2).there is already 2 as a no...it should be ...4,3
  
• 9 years agoHelpfull: Yes(3) No(0)
• for 6 number divisible by 2 and 3
  count =0
  _12 only 3 count = 1
  _14 not possible
  _24 or _42 only 3 count =3
  _32 ...2 and 1 count = 5
  _34....5 and 4 count = 7
  _52 not possible
  _54 only 3 count =8
  if number not repeated
  ans is 8
• 9 years agoHelpfull: Yes(2) No(3)
• not complete question
  
• 9 years agoHelpfull: Yes(2) No(1)
• rakesh,,how u took x+y+2=9 and x+y+4=9 ,when the sum should be divisible by 2 ,3
  explain
  plzzz
  
• 9 years agoHelpfull: Yes(1) No(0)
• 12,42,24,54,132,312,342,432,324,234 total 10 nos
  
• 9 years agoHelpfull: Yes(0) No(2)
• 152,132,312,342,432,512,234,324,354,534,
  total 10 no
  
• 9 years agoHelpfull: Yes(0) No(4)
• (11)
  if repitition allowed
  112,152,132,312,342,432,512,234,324,354,534
• 9 years agoHelpfull: Yes(0) No(1)
• ______ _____ _______ _____1___ ______2____ -------->1X2x3x1x1----->6 ways
  _______ _____ _______ _____2____ ______4___ ---------->6 ways
  ______ ______ ______ ______5____ _____4____ -------->6 ways
  ans----->18
• 9 years agoHelpfull: Yes(0) No(0)
• @RAKESH how can you assume three digits no.
  if we assume two digits no then three more no which is disible by 6
  similarly for four digits no and 5 digits no as well.
• 9 years agoHelpfull: Yes(0) No(0)
• NOTE: A number is divisible by 6 if it is even and if the sum of its digits is divisible by 3.
  
  NOW in this case sum of all the digits (1+2+3+4+5=15) is divisible by 3.
  Now only 2 option arise to get an even number.
  case 1. __ __ __ __ 2 or
  case 2. __ __ __ __ 4
  so the required combination will be .... for case 1.- 4*3*2*1=24 Case 2- 4*3*2*1= 24
  hence 24+24=48 is the answer
• 8 years agoHelpfull: Yes(0) No(0)
• one digit number 0
  two digit number (12)(24)(42)
  three digit number (132)(312)(354)(534)
  four digit number (1254)(1524)(5124)(5214)(2154)(2514)(1452)(1542)(5412)(5142)(5142)(4512)
  five digit number (ending with 4 is 4*3*2*1= 24)(ending with 2 is 4*3*2*1=24)
  total= 67
• 8 years agoHelpfull: Yes(0) No(1)
• Nimber of Numbers to be formed, i.e
  
  1 digit no. - 0
  2 digit no. - 4 --> (12,24,42,54)
  3 digit no. - 8 --> combination of possible numbers (234) and (345)
  4 digit no. - 24 --> combination of possible numbers (1245)
  and
  5 digit no. - 48 --> combination of possible numbers (12345)
  so total possible numbers are 0 + 4 + 8 + 24 + 48 = 84
• 6 years agoHelpfull: Yes(0) No(0)
• 1 digit number=0
  2 digit number=12,24,42,54 =>total=4
  3 digit number=132,312,432,342,234,324,534,354=>total=8
  4 digit number:
  last digit of each number must be 4 or 2 so,
  for last digit as 4: 1254 the 1st 3 digits arrange them self in 3! ways so total number=6
  for last digit as 2:1452 the 1st 3 digits arrange them self in 3! ways so total number=6
  hence total 4 digit number=6+6=12
  now 5 digit number=4! x 2!=48
  so total numbers form=>4+8+12+48=72(ans)
• 6 years agoHelpfull: Yes(0) No(0)