In zoo there are deer and peacocks total no of heads 80 and total no of legs 200 then how

Let x and y be the number of deer and peacocks in the zoo respectively. Then,

x + y = 80 ...(i) and

4x + 2y = 200 or 2x + y = 100 ...(ii)

Solving (i) and (ii), we get) x = 20, y = 60.
10 years agoHelpfull: Yes(2) No(0)
deer having 4 legs so assume 20*4=80 legs and 20 heads
peacock having 2 legs so assume 60*2=120 legs and 60 heads
total 80 heads and 200 legs are obtains so answer is 60
10 years agoHelpfull: Yes(1) No(0)
let x no of peacock and y no of deer
then x+y=80
2x+4y=200
hence 20deer and
60 peacock are there
10 years agoHelpfull: Yes(1) No(0)
ans is 60.
let x be num of deer
y be num of peacocks.
x+y=80
4x+2y=200
solving by elimination method, we get x=20,y=60
10 years agoHelpfull: Yes(0) No(0)
60
x=dear
y=peacocks
x+y=80
4x+2y=200
x=20
y=60
so the ans is y=60
10 years agoHelpfull: Yes(0) No(0)
4x+2y=200-(1)
x+y=80 -(2)
so x=20 &y=60
10 years agoHelpfull: Yes(0) No(1)
(60 peacocks*2)+(20 deers *4)=120
peacocks =60
10 years agoHelpfull: Yes(0) No(0)
let the no of deer be x, no of peacock be (80-x)
4x+2(80-x)=200
x=20
then
no of deer be 20 and peacock be 60
5 years agoHelpfull: Yes(0) No(0)

In zoo there are deer and peacocks. total no of heads 80 and total no of legs 200 then how many peacocks are there