In a group of 120 people 90 have an age of more 30yrs and the other have age of less then 20 yr.if a person is selected at random from htis group .what is the probability the person's age is less than 20.

0.25
0.33
0.42
0.52

• Total no. of people = 120
  No. of people having age more than 30 = 90
  Probability(people having age more than 30) = 90/120 = 3/4
  Remaining no. of people = 120-90 = 30
  Probability(people having age less than 20) = 30/120 = 1/4 = 0.25
  
  Ans : 0.25
• 10 years agoHelpfull: Yes(21) No(1)
• 0.25 will be the aswer
• 10 years agoHelpfull: Yes(2) No(1)
• 30c1/120c1
• 10 years agoHelpfull: Yes(2) No(0)
• Ans:0.25
  Total no people=120
  more 30yrs age=90
  probability of more 30yrs age=90/120=3/4
  others=120-90=30
  probability of others less than 20=30/120=1/4=0.25
  
• 10 years agoHelpfull: Yes(2) No(0)
• 30c1/120=1/4=0.25
• 10 years agoHelpfull: Yes(1) No(0)
• Ans= c(30,1)/c(120,1)
  =30/120
  = .25
• 10 years agoHelpfull: Yes(1) No(0)
• 0.25,as prob. of person's having less than 20 is 120-90/120=1/4=0.25
• 10 years agoHelpfull: Yes(1) No(0)
• probability (getting age below 20 yr)=30120=0.25
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• 30/120=0.25
• 10 years agoHelpfull: Yes(0) No(0)
• 0.25 is the right answer
  
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• .25
  30/120=.25
  
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• 30c1/120
  =1/4
  =0.25
• 10 years agoHelpfull: Yes(0) No(1)