how many zeroes at the end of 50!?

• 50/5^1 = 10
  50/5^2 = 2
  
  Total no. of zero's ll be 10 + 2 = 12
  
  Ans : 12
• 9 years agoHelpfull: Yes(30) No(1)
• 
  For calculating the no. of zero's at the end of n!, We have to divide n by successive powers of 5...
  n/5^1 + n^5^2 + n/5^3 + ... till the quotient gives a non-zero value...
  Note here we have to consider only the quotient... remainder should be neglected...
  
• 9 years agoHelpfull: Yes(12) No(0)
• 50/5=10
  10/5=2
  10+2=12...
• 9 years agoHelpfull: Yes(4) No(1)
• Why are v dividing it by 5 only
• 9 years agoHelpfull: Yes(3) No(0)
• 10=5*2. the no. of 5s in 50! is less than the no. of 2s.
  therefore, the no. of 0s at the end will be equal to the highest power of 5 in 50!.
  50/5=10
  10/5=2
  2/5=0
  therefore, no. of 0s at the end=10+2+0=12
• 9 years agoHelpfull: Yes(2) No(0)
• (50/5^1)+(50/5^2)= 10 + 2 =12
  
  Answer : 12
• 9 years agoHelpfull: Yes(1) No(0)
• 50/5=10
  50/25=2
  
  total zero=10+2=12
• 9 years agoHelpfull: Yes(0) No(1)
• How did u do that @saraswathy
• 9 years agoHelpfull: Yes(0) No(1)
• I count the numbers that end in zero, namely 10,20,30,40,50 (that
  will put 5 zeroes at the end of our answer.
  
  and,50 has to be counted twice because
  50 is 5 x 10. For example, if you multiply 50 by an even number like
  50 x 4, you get 200, which has 2 zeroes at the end.
  
  =>5+1=6 zeroes
  
  Then the numbers that
  end in 5 are 5,15,25,35,45 (There are 5 of them, but don't forget
  that 25 is multiples of 5^2, so we have to count it twice).
  
  =>5+1 zeroes
  
  so, finally
  6+6=12 zeros for 50!
• 9 years agoHelpfull: Yes(0) No(1)
• 12 i.e 25/2
• 8 years agoHelpfull: Yes(0) No(0)
• why all of u dividing the nmbr by 5, 5^2,... why not by 2, 3,4,6 etc.plzz tell me
• 5 years agoHelpfull: Yes(0) No(0)