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no. of prime factors of 30^7 x 22^5 x 34^11 ?
Read Solution (Total 8)
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- 30^7 * 22^5 * 34^11
(2*3*5)^7 * (2*11)^5 * (2*17)^11
=> 2^23 * 3^7 * 5^7 * 11^5 * 17^11
Total no. of prime factors ll be => (23+7+7+5+11) = 53
Ans : 53 - 10 years agoHelpfull: Yes(31) No(7)
- 30^7*22^5*34^11=3^7*2^23*11^5*5^7*17^11
no of factors=(7+1)(23+1)(5+1)(7+1)(11+1)=8*24*6*8*12=110592 - 10 years agoHelpfull: Yes(15) No(10)
- Answer:53
(2*5*3)^7=7+7+7=21
(2*11)^5=5+5=10
(2*2*2*3)^11=11+11=22
Total:21+10+22=53
- 10 years agoHelpfull: Yes(8) No(3)
- My answer is 53
30=2*3*5___ 3 prime numbers as 30^7 total prime numbers are 7*3=21
22=2*11___ 2 prime numbers,same as above total (2*5)=10
34=2*17___ 2 prime numbers,same as above total (2*11)=22
total prime numbers 21+10+22 =53
- 10 years agoHelpfull: Yes(3) No(2)
- 2,3,5,11,17 so there r 5 prime factor
- 9 years agoHelpfull: Yes(3) No(1)
- 30= 3*2*5
22=2*11
34=2*17
hence the prime factors are 2,3,5,11,17.
But here they have asked number of prime factor which means total ow much prime factor are there.
So there are 5 prime factor if we started counting from 2 to 17.
Hence answer is 5 - 8 years agoHelpfull: Yes(2) No(0)
- instead of this if total no of factors was asked then what would be the soln..(24+8+8+6+12)???????/
- 9 years agoHelpfull: Yes(0) No(1)
- ans 53.......
- 9 years agoHelpfull: Yes(0) No(1)
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