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A cake seller sells one cake at a profit of 10% and sells another at a loss of 5%. Let the ratio of the CPs of the cakes is 2:3 respectively. Find his net profit or loss percentage.
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- Let the CPs of the cakes be 2x and 3x
Hence net CP = 5x.
SP of first cake = (110/100)*2x = 220x/100
SP of second cake = (95/100)*3x = 285x/100
Net SP = (220x/100) + (285x/100) = 505x/100 = 5.05x.
SP is greater than CP and his profit is 5.05x - 5x = .05x.
His profit percentage = (.05x/5x)% = .01%. - 12 years agoHelpfull: Yes(9) No(12)
- 1%gain will be the correct answer.
- 9 years agoHelpfull: Yes(1) No(0)
- Let the CPs of the cakes be x1 and x2
Given, x1/x2 : 2/3
ie, x2=(3/2)x1
SP of first cake = (110/100)*x1 = 110x1/100
SP of second cake = (95/100)*x2 = (95/100)*(3/2)x1
= 285x1/200
Net SP = (110x1/100) + (285x1/200) = 505x1/200 = 2.525x1
Total CP=2x1+3x1 =5x1
CP is greater than SP So,
Loss = 5x1 - 2.525x1 = 2.475x1
So, Loss percentage = (2.475x1/5x1)% = 0.495%.
Aprox Loss = 0.5%
LOSS OF 2.475 - 11 years agoHelpfull: Yes(0) No(3)
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