In class of 150 students- 40 passed in physics and chemistry, 40 passed in physics and maths, 30 passed in maths and chemistry and 10 students passed in all three subjects.
1) How many students passed only in maths.
a)40 b)30 c)20 d) indeterminate

2) If no student fail in all three subjects then what is the total no. of student who passed physics only,chemistry only,maths only.
a) 40 b) 50 c) 60 d) indeterminate

plz solve this Q and explain it..thank u

• it cant be determined.........as we dont know how many students were failed in which subject.
  
  for 2 nd part we use set theory
  p(MUCUP)=P(M)+P(C)+P(P)-P(M intersection P)-P(M intersection C)-P(C intersection P)+P(PUMUC)
  by solving
  p(M)+(C)+P(P)=50
• 10 years agoHelpfull: Yes(13) No(4)
• please be clear.. even following ua formulae is not giving correct ans
• 10 years agoHelpfull: Yes(3) No(0)
• here by using venn diagrams we can solve
  otherwise probability
  let take probability
  P(MUPUC)=P(M)+P(C)+P(P)-P(M INSERTION P)-P(M INSERTION C)-p(C INSERSTION P)+p(M INSERTION P INSERTION C)
  15O=P(M)+P(C)+P(P)-40-40-30+10
  P(M)+P(C)+P(P)=50
  THEN BY USING VENN DIAGRAM
  
  P(M)=150-(P(M)+P(C)+P(P)+P(M INSERTION C)+P(M INSERTION P)+P(M INSERTION C INSERTION P))
  P(M)=150-(50+40+30+10)
  P(M)=20
  P(C)=150-(P(M)+P(C)+P(P)+P(M INSERTION C)+P(C INSERTION P)+P(M INSERTION C INSERTION P))
  P(C)=150-(50+40+30+10)
  P(C)=20
  P(P)=150-(P(M)+P(C)+P(P)+P(P INSERTION C)+P(M INSERTION P)+P(M INSERTION C INSERTION P))
  P(P)=150-(50+40+40+10)
  P(P)=10
  
  
  THANK YOU
• 8 years agoHelpfull: Yes(1) No(4)
• By the help of venn diagram, we can get the answer
  1) d) indeterminate
  2) c) 60
• 8 years agoHelpfull: Yes(1) No(1)
• 1)20 ...apply your sense...if p+c=40 and p+m=40 and m+c=30 so no. of pass in maths would be either 20 or 10 now...options given 20 so 20
  2)50 in maths 20 passed...in chemistry 30-20=10 passed and in physics 40-20=20.....so 20+20+10=50
  
• 8 years agoHelpfull: Yes(0) No(0)