m=2- root 3
Find the value of:
(m^6+m^5+m^4+1)/m^3

• m = (2 - √3)
  => 1/m = (2 + √3)
  
  (m^6+m^5+m^4+1)/m^3
  = m^3 + m^2 + m + 1/m^3
  = (m + 1/m)^3 - 3(m +1/m) + m(m+1)
  = 4^3 - 3*4 + (2-√3)(3-√3)
  = 64 - 12 + 9 - 5√3
  = (61 - 5√3)
• 10 years agoHelpfull: Yes(17) No(3)
• m=2- √3
  ((2-√3)^6+(2-√3)^5+(2-√3)^4+1)/(2-√3)^3
  ((2-√3)^6+5+4)+1)/((2-√3)^3
  ((2-√3)^15)+1/(2-√3)^3
  (((2-√3)^15/(2-√3)^3)+1)/((2-√3)^3)
  ((2-√3)^5)+((2-√3)^-3)
  (2-√3)^5-3
  (2-√3)^2
  4-4√3+3
  7-√3
  
• 8 years agoHelpfull: Yes(0) No(6)
• first of all we have to find the value of root 3 that is 1.732
  then subtract it from 2 we will get 0.268
  we have to take the given powers of m.Then by adding them we will get 3.412
  for this value we have to divide it by 3 times of m.
  the final answer we will get is 38.198
• 6 years agoHelpfull: Yes(0) No(0)