Elitmus
Exam
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A car goes from A to B with certain velocity.Due to some problem in the engine after travelling 30 km,it goes in 4/5th of actual velocity and reach B 45 minutes late.If engine fails after 45km,then reach B 36 minutes late.Find velocity and distance between A and B.
Read Solution (Total 5)
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- the answer is
initial velocity is 25 km/hr
and distance is 105 km
explanation
let distance = xKm and Velocity = yKm/hr
form 2 equations
total time = time from start to first break point+ time
from first breakpoint to destination
(time = distance/speed)
total time fromassumption = (x/y)
for first case
total time = (x/y)+(3/4){36 minutes converted into hrs}
time from start to first break point = (30/y)
time from first break point to destination = (x-30/(4/5y))
{since velocity has decreased to 4/5}
hence
x/y + 3/4 = 30/y + (x-30/(4/5y)) .......... equatiion 1
similarly equation 2 is derived from 2nd case given as:
x/y + 3/5 = 45/y + (x-45/(4/5y)) .......... equatiion 2
solving v get x=105
and y = 25
its seems to be lengthy in reading the solution but trust
me it wont take more than 2 mins to solve the question - 10 years agoHelpfull: Yes(7) No(0)
- let the total distance=x
the difference in time is 45 m =3/4 hr
30/v+(x-30)5/4v-x/v=3/4........................1
45/v+(x-45)5/4v-x/v=3/5.........................2
after euating 1 and 2
5x-12v=225
4x-12v=120
solve
we get x=105 and v=25
- 10 years agoHelpfull: Yes(4) No(0)
- Car gets late 45-36=9min when it covers 45-30=15km by 4/5 of actual velocity
so it will take 15*5=75km to get late by 9*5=45 min
so total distance=30+75=105
alternate
let the total distance =x
let the velocity = 5y
1. (x-30)/4y - (x-30)/5y = 45/60
2 (x-45)/4y - (x-45)/5y =36/60
by solving eq 1&2---->x=105, velocity=5y=25
- 10 years agoHelpfull: Yes(2) No(0)
- velo=25kmph and Dist=105km..
convert minutes to hour and then simple two equation two variables - 10 years agoHelpfull: Yes(1) No(3)
- velocity = 25, distance=105
- 10 years agoHelpfull: Yes(0) No(0)
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