Contractor has 2 complete work within a fixed time. If he is late he has to pay fine. The first day it is Rs 200 and from then on it increases by 25 per day. He has to pay Rs 9450. How many days he got late.

• answer is 21.....200,225,250,....,9250.
• 9 years agoHelpfull: Yes(4) No(1)
• 9450-200=9250
  Now 2 nd day he will pay 225...then 250....up to 9250
  Here common difference=25
  First term =225
  Last=9250
  So 9250=225+(n-1)25
  (N-1)25=9025
  N-1=361
  N=362
  Delay=363
• 9 years agoHelpfull: Yes(2) No(6)
• the answer is 21
  
• 9 years agoHelpfull: Yes(1) No(1)
• 200+225+250+275+300+325+350+375+400+425+450+475+500+525+550+575+600+625+650+675+700
  just add the answer will be 9450
  
• 9 years agoHelpfull: Yes(1) No(1)
• the solution is sum of ap
  a=200 d=25 n=? sum=9450
  if we use formula s=n/2[2a+(n-1)d]
  then we get quadratic equation on solving it answer is 21
• 8 years agoHelpfull: Yes(1) No(0)
• can any one explain how 21 came?
  
• 9 years agoHelpfull: Yes(0) No(0)