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Maths Puzzle
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What are last two digits of 72008
A.
21
B.
61
C.
01
D.
41
Read Solution (Total 3)
-
- There is a pattern in the last digits. Since 7^2008 is a ridiculously huge number, we don't bother with computing it.
So 7^1=7
7^2=49
7^3=343
7^4=2401
7^5=16807 - 10 years agoHelpfull: Yes(1) No(2)
- wts the answer ?? plzz explain it..?
- 10 years agoHelpfull: Yes(0) No(0)
- c) 01
7^(4*(some value))=.....01 - 10 years agoHelpfull: Yes(0) No(1)
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