Accenture
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Numerical Ability
Ratio and Proportion
729 ml of a mixture contains milk and water in ratio 7:2. How much of the water is to be added to get a new mixture containing half milk and half water?
(i) 79 ml
(ii) 81 ml
(iii) 72 ml
(iv) 91 ml
Read Solution (Total 6)
-
- ans should be 405..
wrong options or wrong ques - 12 years agoHelpfull: Yes(30) No(3)
- milk=(7/9)*729=567
water=(2/9)*729=162
according to question let z ml of water is added of mixture so
(729+z)*(50/100)=162+z
on solving
z=405 ml - 12 years agoHelpfull: Yes(26) No(5)
- lets take 7+2=9parts
1part=729/9=81
old mixture contains 7parts of milk and 2 parts of water.(7:2)
to get new mixture containing half milk and half water add 5parts of water to the old mixture then 7:(2+5)
so.....5*81=405ml - 12 years agoHelpfull: Yes(14) No(3)
- quantity of water 2/9 of 729 =162
qunt of milk 7/9 of 729 =567
for half milk and water it 364.5 each
so for half water 364.5-162=202.5 ml needed - 12 years agoHelpfull: Yes(6) No(20)
- by ratio 7:2 we calculate the volome of milk and water individually
therefore milk = 567ml and water = 162ml
now we add x ml of water so that the ratio is 7:3
equating the volume of water we get
162+x = (3/10)*(729+x)
solve for x we get
x=81 ml - 10 years agoHelpfull: Yes(5) No(7)
- Solution:
Milk = (729 * (7/9))=567ml
Water = (729-567)= 162ml
Let water to be added be x ml 567/(162+x) = 7/3 1701 = 1134 + 7x
x = 81ml - 10 years agoHelpfull: Yes(1) No(4)
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