'how to make sum 30 using 1,3,5,7,9,11,13,15.
any 5 numbures must be in use and you can
repeat the numbures?

• 11+9+5+3+1+1=30
• 9 years agoHelpfull: Yes(20) No(14)
• You cannot get even number by adding 5 odd numbers. I dont know whether i am right or wrong, check my solution:
  
  15^1 + 5 + 5 + 5 = 30
• 9 years agoHelpfull: Yes(13) No(12)
• 3+7+5+15=30
• 9 years agoHelpfull: Yes(7) No(7)
• (1^3)+9+5+15=30
• 9 years agoHelpfull: Yes(6) No(5)
• 3!+11+13=30
• 9 years agoHelpfull: Yes(6) No(5)
• 3!+3!+3!+3!+3!
• 9 years agoHelpfull: Yes(0) No(1)
• 1+9+5+7+3+5=30
• 9 years agoHelpfull: Yes(0) No(0)
• a) 3!+1+3+11+9=30
  b) 3!+1+3+15+5=30
  c) 3!+1+3+13+7=30
  
  where,
  3! -> Factorial of 3 -> 1*2*3=6
  
  Summing up, we get 30.
• 9 years agoHelpfull: Yes(0) No(0)
• 9+7+1.5+3.5+9 = 30
• 9 years agoHelpfull: Yes(0) No(0)
• Please read the catch-phrase
  "repetition is allowed" where the trick lies.
  that means on the top of 5 digits, a no. can be repeated
  11+9+5+3+1....+1
• 9 years agoHelpfull: Yes(0) No(0)
• we can never arrive at 30 by adding 5 odd numbers becoz the sum of 5 odd numbers is always odd. But here 30 is even . SO IMPOSSIBLE!!!!!!!!!!!!!! We can either add 4 odd numbers or 6 odd numbers to arrive at 30.
  Eg: 13+7+7+3=30 (adding 4 numbers)
  or 7+3+3+3+5+9=30 (adding 6 numbers)
  or 15+15=30 (adding 2 numbers)
  Which means we can add only even number of odd numbers to get the sum even i.e 30.
• 9 years agoHelpfull: Yes(0) No(0)
• 1,3,7,9 and 5 twice
  
  1+3+7+9+5+5=30
• 9 years agoHelpfull: Yes(0) No(1)
• 3+5+7+15ˆ1=30
• 4 years agoHelpfull: Yes(0) No(0)