On children’s day sweets were to be equally distributed amongst 200 children. But on that particular day 40 children remained absent; hence each child got 2 sweets extra. How many sweets were distributed? shortcut trick

• let x be the number of sweets is given to each student.
  Then, 200*x = 200x(total number of sweets distributed)
  
  and 160*(x+2)= 160x+32(total number of sweets)
  
  160x+320 = 200x
  320=40x
  x=80
• 10 years agoHelpfull: Yes(2) No(0)
• total 200
  absent 40
  200-40=160
  each got 2 means 160*2=320
• 10 years agoHelpfull: Yes(1) No(0)
• 1600
  
  If each student got 'x' sweets when their strength is 200
  So total number of sweets= 200x ---(i)
  When students are 160, each student got 'x+2' sweets
  Total number of sweets= 160(x+2) ---(ii)
  As number of sweets in both the case is same, 200x= 160(x+2) ,x=8
  So total number of sweets= 200x or 160(x+2)= 1600
  
  OR
  
  If number of sweets= x
  Sweets each students got,when they are 200= x/200 ---(i)
  Sweets each students got,when they are 160=x/160 ---(ii)
  Each student in (ii) got 2 extra than the (i)
  So, (x/200)+2 =x/160
  (x+400)/200= x/160 ,On solving,x=1600
• 10 years agoHelpfull: Yes(0) No(0)
• let x is the no of sweets given to each children.
  total sweets=200x
  absent=40
  200-40=160
  160(x+2)=200x
  160x+320=200x
  x=8
  total sweets=200*8=1600.
• 10 years agoHelpfull: Yes(0) No(0)