A train running at a speed of 40 kph crosses a platform double its length in 32.4 seconds.what is the length of the platform?

• length of train x
  length of platform 2x
  
  40*5/18=3x/32.4
  x=120
  
  platform length =240
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• 2*(40*5/18*32.4)=720
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• Correct ans is 120
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• let length of train be X
  then length of platform be 2X;
  to cross the platform train cover the distance=2X+X;
  =3X
  now
  3X=32.4*40*5/18;
  X= 120;
  hence length of th platform=240
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• d=s*t
  40*(5/18)=11.11m/sec(sec->11.11then for 32.4??=32.4*11.1)
  11.11*3.24=360m
  leangth of the platform is 360m
  
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