p and a do work in 40 and 25 days.they work together but p left after some days and a finish remaining work in 12 days. after how many days did p leave?

ans:8days

• (p+a)'s 1 day work is (1/40+1/25) = 13/200
  let they work for x days and after that p left.
  Therfore, (p+a)'s x days work togethor = (13/200)*x
  Now, Remaining work = 1-(13*x/200) = (200-13*x)/200
  
  This remaining work is to be done by a alone.
  
  We know that a's 1 day work is 1/25
  Therefore, a's 12 days work = 12/25
  
  12/25 = (200-13x)/200
  x=8
• 10 years agoHelpfull: Yes(2) No(0)
• let p work for x days;
  hence, a work for x+12 days;
  now
  (x/40)+(x+12)/25=1;
  x=8;
• 10 years agoHelpfull: Yes(2) No(0)
• total time taken by A be x
  time taken by A&P x-12
  
  x/25+(x-12)(1/25+1/40)=1
  
  by solving x=256/21
• 10 years agoHelpfull: Yes(0) No(3)