1. The H.C.F of two numbers is 12 and their L.C.M is 360. If one of the numbers is 36. Find the other number?

• given n1=36;
  and n2=???
  
  as we know, n1*n2 = HCF*LCM
  36*n2= 12*360
  => n2=120 ;
• 10 years agoHelpfull: Yes(11) No(0)
• Other no = 12*360/36
  =120.
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• other no= (12*360)/36=120
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• h.c.f*l.c.m=product of two numbers
  12*360=36*x
  x=120
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• 12*360/36=120
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• as we know that hcf * lcm=product of numbers;
  therefore 12 * 360 = 36 * x
  x=120.
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• we know that the product of two numbers=HCF*LCM
  so other number=12*360/36=120
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• hcf*lcm = n1+n2 ,so 12*360=36*n2
  i.e,120
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• other no=(L.C.M*H.C.F)/one no
  =(12*360)/36=120
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• n2=(12*36)/36=120
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• number=120;
  hcf*lcm = multiplication of number;
  12*360=x*36;
  x=120;
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• as we know hcf*lcm=product of two no.
  let the no is=x
  12*360=36*x
  =>x=12*360/36
  =>x=120.
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• 120 bcoz product of hcf and lcm equals product of two no.
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• HCF=12,
  LCM=360,
  n1=36,n2=?
  
  n1*n2= hcf *lcm,
  
  36*n2=12*360,
  
  n2=12*360/36
  
  n2=12*10=120
  
  
  
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• Ans:120
  36*x=12*360
  36*x==4320
  x=4320/36
  x=120
  
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• L.C.M * H.C.F = Product of two no.s
  so 2nd no is (12*360)/36
  =120
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• HCF=12,LCM=360
  We know HCF x LCM = product of two numbers & here one number which is provided is 36.
  Therefore, (360*12)/36= 120 is the answer.
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