In a certain examination papers there are n questions,for j=1,2,...n there are
2^n-1 studentswho answered j or more questions wrongly..if the total no of wrong answers is 4095,then the value of n is:

• 2^n-1=4095
  2^n=4096
  2^n=2^12
  n=12
• 10 years agoHelpfull: Yes(22) No(1)
• =>2^n - 1 =4095
  =>2^n=4096 or 2^12
  n=12
• 10 years agoHelpfull: Yes(1) No(1)
• answer is 11
  since 2^n-1
• 10 years agoHelpfull: Yes(1) No(1)
• Make a correction-,'2^(n-j) students answered j questions wrongly'.
  Number of wrong answers=2^(n-1)+2^(n-2)+ ...+2^(n-(n-1))+2^(n-n)=2^n-1.
  Therefore, 2^n-1=4095 => n=12.
• 10 years agoHelpfull: Yes(1) No(0)
• 2^N-1=4095;
  2^N=4095+1=4096
  2^12=4096
  SO ANS IS:12
• 10 years agoHelpfull: Yes(1) No(0)
• 4096=2^12
  4096-1=4095
  so n=12
• 10 years agoHelpfull: Yes(0) No(0)
• 2^N-1=4095;
  2^N=4095+1=4096
  2^16=4096
  SO ANS IS:16
• 10 years agoHelpfull: Yes(0) No(10)