two boats sailing into a sea on two sides of the lieghthouse.elevation of leight house is observed from two bpats are 30 degrees and 45 degrees.and height of the leighthouse is 100m.what is the distance between two boats

• consider a triangle, with a line joining the vertex and the opposite side ie. the ht of lighthouse 100m..now consider the angle to the left of lighthouse as 30 n right as 45..therefore tan 45 = 100/x...x= 100. again tan 30 = 100/y..y= 173.2..hence the distance between d 2 boats = x+y = 273.2
• 10 years agoHelpfull: Yes(1) No(1)
• tan 30=100/x, x=100/tan 30=173.2
  tan 45=100/y,y=100/tan 45=100
  x+y=273.3
• 10 years agoHelpfull: Yes(1) No(1)
• Frm the question it's clear tht angle of elevation fr 2 boats frm light house is 30 n 60 degrees. Height of the light house is 100. So when a diagram is drawn u get a triangle with a line frm tip of the triangle to the horizontal line.(distance b/w 2 boats)
  So frm trignomerty u can individually find the disatance b/w 2 boats .
  Use tan 30 and tan 45 with height of lighthouse (as opp side) to find adjacent sides respectively n add them.
  So u get 100+100√3m.
• 8 years agoHelpfull: Yes(0) No(0)