A takes twice as much time as B or thrice as much time as C to finish a piece of work. Working together, they can finish the work in 2 days. B can do the work alone in:

• 1/x + 2/x + 3/x =6/x = 2
  
  x=6*2=12
  x is time for a. so time for b = 12/2(half the time)=6
• 10 years agoHelpfull: Yes(2) No(0)
• 6 Days
  
  If A,B & C alone can complete the work in a, b & c days respectively,
  1 day work of A=1/a=1/(2b) ---(i) & 1/a =1/(3c) ---(ii)
  From (i) & (ii), 1/c=3/(2B)
  As 1 day work of A,B & C together=1/2 ,So (1/a)+(1/b)+(1/c)=1/2
  or 1/(2b) + 1/b + 3/(2b) =1/2
  On solving, b=6
  
  
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• b requires 11/6 days
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• sorry 6 days
  
• 10 years agoHelpfull: Yes(1) No(1)
• here A takes X days B=x/2,c=X/3 days to complete a job.
  one day work of each=1/x+2/x+3/x=1/2
  x=12
  B done it in X/2=12/2=6 days
• 10 years agoHelpfull: Yes(1) No(0)