Elitmus
Exam
Logical Reasoning
Cryptography
3rd august question
KNV
AMN
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AVEE
RMEW
WENF
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ANNVGE
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Read Solution (Total 15)
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- any bdy wnt 2 learn shrtcts of crpyt by wch u cn slve any crypt in jst 2 min
- 10 years agoHelpfull: Yes(70) No(1)
- 947
*364
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3788
5682*
2841**
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344708
------- - 10 years agoHelpfull: Yes(6) No(1)
- @Anan Kumar plzz tell how can we solve crypt question in 2 min .share with us
- 10 years agoHelpfull: Yes(6) No(0)
- 947
x 364
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3788
5682x
2841xx
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344708 - 10 years agoHelpfull: Yes(3) No(0)
- i used 2 tch sm stdnts it is free of cst nd stdy online it is my passn so u cn cntct me fb
- 10 years agoHelpfull: Yes(3) No(0)
- n*v=e = 4*7=8
c+ n*n=e = 2+4*4=8
c+ n*k=av= 1+4*9=37
947
364
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3788
5682
2841
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344708
- 10 years agoHelpfull: Yes(2) No(0)
- first try to find zero, after deep analysis you find that G is zero.
now try to find 1, you will find R and F remains for 1, if you take R as 1 then E must be 8 or 9(as R+E through carry),if E=8 then F must be 1 which is not possible as R is 1 and if E=9 then F must be zero which is also not possible as G=0.So R will not be 1 so F will be 1.once we get the value of F then we can calculate the value of E(as E+F=9) ,From E we can find W(as E+W=10) Form W we can find A(as A+M=9) and so on - 10 years agoHelpfull: Yes(2) No(0)
- 947
364
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3788
5632*
2821**
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34478 - 10 years agoHelpfull: Yes(1) No(0)
- yes anan we want to learn plzz tell us
- 10 years agoHelpfull: Yes(0) No(0)
- anan sir ys i wnt wr is ur cochn cntr nd mntn ur fee
- 10 years agoHelpfull: Yes(0) No(0)
- It takes me hour to solve is there any short cut method for these type of questions
- 10 years agoHelpfull: Yes(0) No(0)
- How to contact you mr ANAN KUMAR
- 10 years agoHelpfull: Yes(0) No(0)
- 947
*364
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3788
5682
2841
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344708 - 10 years agoHelpfull: Yes(0) No(0)
- How to contact u Mr. Anan. I want the shortcuts to solve this type of problems. pls can u explain
- 10 years agoHelpfull: Yes(0) No(0)
- w+1=a,A+M+N=N from this A+m=9 n from another coloumn E+F+V=V E+F=9 make pair of (A,M) and (E,f)...i solved it tryin out this trick
- 10 years agoHelpfull: Yes(0) No(0)
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