if there are 44 diognals in a polygon then how nany sides are there ?

• polygon with n sides have n(n-3)/2 diagonals so,
  2*44=n^2-3n
  n^2-3n-88=0
  solving the equation v get roots as n=11 and -8
  therefore ans is 11
• 9 years agoHelpfull: Yes(1) No(0)
• Number of diagonals = nC2 - n
  
  Where n is the number of sides.
  
  44 = nC2 - n
  n! /(n-2)!*2! - n = 44
  n^2 -3n -88 = 0
  n = 11 , -8
• 9 years agoHelpfull: Yes(0) No(0)
• no of diagonals = n(n-3)/2 = 44
  = 11(8)/2 = 44
• 9 years agoHelpfull: Yes(0) No(0)