CSC Company Numerical Ability Time Distance and Speed

A train moving at 2/3 rd of its normal speed reaches its destination 20 minutes late. Find the normal time taken?

a) 1 hour b) 1/3 hour c) 2/3 hour d) 3/4 hour

Read Solution (Total 2)

Option C
Let the original speed and time is S and T
then distance =S*T
Now the speed changes to 2/3S and T is T+20
As the distance is same
S*T=2/3S*(T+20)
solving this we get t=40 minutes
=40/60=2/3 hour
12 years agoHelpfull: Yes(2) No(0)

if train moving at (p/q) rd of its .........and time destination is (t) minutes
then solution is (q-p)*t
so (3-2)*20=20minutes
20/60=2/3
9 years agoHelpfull: Yes(0) No(0)

CSC Other Question

The ratio of managers to management trainees is 3 : 5. When 21 new management trainees are recruited the ratio will become 3 : 8. How many managers will be there in the group?

a) 27 b) 24 c) 21 d) Cannot be determined The marked price of a book is 20% more than the cost price. After the book is sold, the vendor realizes that he had wrongly raised the cost price by a margin of 25%. If the marked price of the book is Rs.30, what is the original cost price of the book?

a) Rs.30 b) Rs.25 c) Rs.45 d) Rs.20