what is the maximum remainder when xxyyzz is divided by 1001???
1. 990
2. 121
3. 897
4.?

• take 110099 as X!=Y!=Z
  110099%1001= 990
• 10 years agoHelpfull: Yes(8) No(18)
• question is incomplete.. its also given that x!=y!=z
  so x=1, y=0, z=1
  110011%1001 = 902
  22224%1001 = 202
  33336%1001 = 303
  
  max= 902
• 10 years agoHelpfull: Yes(6) No(6)
• gaurav plz tell how u get z=9
• 10 years agoHelpfull: Yes(4) No(0)
• As it is given that x!=y!=z
  So The value we can assume x=1, y=1, z=0
  111100/1001
  So we get remainder=990
  
• 10 years agoHelpfull: Yes(4) No(18)
• Answer is 1000
  like we take 200199/1001
  giver remainder 1000
  here we need maximum remainder of 6 digits
  so maximum is always less than 1 digit from divisor
  
  
  
• 10 years agoHelpfull: Yes(2) No(10)
• The answer is 880
• 10 years agoHelpfull: Yes(2) No(1)
• It's answer is 2 i.e 121.
  Take an ex of xx as 44, yy as 55 , zz 66. Then the remainder will be 121.
• 10 years agoHelpfull: Yes(1) No(8)
• in such type of questions...we take 3 digits group and subtract from each other.
  yzz-xxy/1001.In search of max remainder,we do 988-119/1001..we get 869
• 10 years agoHelpfull: Yes(1) No(4)
• yarr gaurav kase kiya explain karo na
• 10 years agoHelpfull: Yes(0) No(1)
• @gaurav hw u take x!=y!=z i think it is not given in the question paper???? without giving hw can u take it???hw u take z=9????
• 10 years agoHelpfull: Yes(0) No(0)
• Take any 3 numbers i.e 223344 and divide by 1001, you will get 121 as remainder.
• 10 years agoHelpfull: Yes(0) No(3)
• please giv the correct answer yaar the solutions are itself an mcq here!!
• 10 years agoHelpfull: Yes(0) No(0)
• 112233%1001=121
  110099%1001=990
  111100%1001=990
  ccannot be determined...if such option is available
  
• 10 years agoHelpfull: Yes(0) No(0)
• @DIMPLE SINGH x,y,z r 3 unequal nums. u can take any value n check it out as @AMAN GUPTA did.
• 10 years agoHelpfull: Yes(0) No(0)
• This is the correct question
  
  What is the maximum remainder when xxyyzz is divided by 1001 where x! = y! = z
  
  u people can check it here: http://www.pagalguy.com/cat/official-quant-thread-for-cat-2014-25104681/2869483
• 10 years agoHelpfull: Yes(0) No(3)
• The answer will be 121..because we can take any value for x,y,z.so suppose we take 1=x,2=y,3=z.Then divided by 1001 we get 121 as a remainder
• 10 years agoHelpfull: Yes(0) No(1)
• number in the form of xxxxxx,xxyxxy,xyxxyx,yxxyxx,xyzxyz are divisible by 1001
  so suppose x=3,y=2,z=1,so number will be 332211
  now use option ,now form option 2 we get 332211+121=332332 whichis divisble by 1001
• 10 years agoHelpfull: Yes(0) No(0)
• I think 121 is the ans
• 9 years agoHelpfull: Yes(0) No(0)
• 121 like e.g=998877
• 8 years agoHelpfull: Yes(0) No(0)