Exam Maths Puzzle Numerical Ability

What will be the last two digits 7^2008 ?

Please Explain the method...!

Read Solution (Total 1)

(7^4)^502
2401^502
so,last 2 digits will be 01
9 years agoHelpfull: Yes(1) No(0)

Exam Other Question

how we can find such pairs of letters are in the word "fore hand" What is the trick for solving following remainder questions?
1. 123123123123/11 = rem
2. 989898/101= rem?
3.(11111*22222*33333)/5 = rem?