4 men & 6 women can complete a work in 8 days, while 3 men and 7 women can complete it in 10 days. In how many days will 10 women complete it?

• let 1 Man alone completes work in M days, then man's 1 day work is 1/M
  let 1 woman alone completes work in M days, then woman's 1 day work is 1/W
  
  given
  4 M & 6 W complete work in 8 days,then 4 M & 6 W , 1 day work is 1/8
  3 M & 7 W complete work in 10 days,then 3 M & 7 W , 1 day work is 1/10
  
  so we get 1 day work equations as
  4(1/M)+6(1/w)=1/8
  3(1/m)+7(1/w)=1/10
  
  on eliminating 1/M
  i/w = 1/40
  =>w = 40
  
  
• 10 years agoHelpfull: Yes(1) No(0)
• sorry ans is 40
  Let a man can complete m work in a day
  and a woman can complete w work in a day
  => (4m + 6w) * 8 = 1 and (3m + 7w) * 10 = 1
  => 4m + 6w = 1/8 ... (1)
  and 3m + 7w = 1/10 ... (2)
  Solving eqns. (1) and (2),
  m = (1/10) (7/8 - 6/10) = 11/400 and
  w = (1/10) (4/10 - 3/8) = 1/400
  
  => one woman can do 1/400 of work in a day
  and 10 women can do 1/40 of the work
  => to complete the work,
  10 women will take 40 days.
• 10 years agoHelpfull: Yes(1) No(0)
• Ans:40 days.
• 10 years agoHelpfull: Yes(0) No(0)
• ans: 16 days.
  solving two equation
  4m+6w=8d
  3m+7w=10d
• 10 years agoHelpfull: Yes(0) No(0)
• lets consider,total work is 1
  one man can do x in 1 day
  and one woman can do y in 1 day
  so the two equations will be
  1)4x+6y=1/8
  2)3x+7y=1/10
  solving this two we get 10y=1/40
  i.e. 10y is work done by 10 women in 1 day
  so they will take (1/10y) days to complete the job
  i.e. 40 days
  so the ANSWER is 40 days
• 10 years agoHelpfull: Yes(0) No(0)