If p,q,r are three consecutive distinct natural numbers then the expression (q+r-p)(p+r-q)(p+q-r) is
A-positive B- negative C-non positive D- non negative

• D- non negative
  
  p,q,r are three consecutive distinct natural numbers
  so, p=x, q=(x+1), r=(x+2) where x is a natural no.
  
  (q+r-p)(p+r-q)(p+q-r)
  = (x+3)(x+1)(x-1)
  = (x^2-1)(x+3) > or = 0 for any x
  so, exp is non negative.
• 9 years agoHelpfull: Yes(33) No(0)
• D- non negative
• 9 years agoHelpfull: Yes(2) No(0)
• non negative
• 9 years agoHelpfull: Yes(1) No(0)
• because sol may be 0 also.....
• 9 years agoHelpfull: Yes(1) No(0)
• 0 is not positive and not negative number so ans D:- non negative
• 9 years agoHelpfull: Yes(1) No(0)
• say p,q,r be a,a+1,a+2 respectively now putting this values we get (a+3)*(a+1)*(a-1) so exprsn bcms (a^2 - 1)(a+3) now natural numbers strt frm 1 so we get 0 puttng 1 otherwise the product is alwys +ve hence D> non-negetive is d ans
• 9 years agoHelpfull: Yes(0) No(0)
• why not A-positive
• 9 years agoHelpfull: Yes(0) No(0)