1947! no. of zeroes

• ans:484
  1947/5=389
  1947/25=77
  1947/125=15
  1947/625=3
  389+77+15+3=484
  
• 10 years agoHelpfull: Yes(3) No(1)
• 1947/5=389
  389/5=77
  77/5=15
  15/5=3
  add->389+77+15+3=484
• 10 years agoHelpfull: Yes(2) No(0)
• find max power of 5 in 1947!....it will be the number of zeros in 1947!
  we are finding out only integer part of x/y
  1947/5+1947/25+1947/125+1947/625+1947+3125=389+77+15+3+0=484
  so 484 wiil be total nof of trailing zeros in 1947!
• 10 years agoHelpfull: Yes(1) No(0)
• 1947/5=389
  1947/25=77
  1947/125=15
  1947/625=3
  then add 389+77+15+3=484. so ans=484
• 10 years agoHelpfull: Yes(1) No(0)