Elitmus
Exam
Numerical Ability
Number System
Find the remainder when 987987987...(upto 132 digit) is divided by 1001
1
14
427
987
Read Solution (Total 10)
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- rem = 0
987987987...(upto 132 digit) / 1001
987987 / 1001 = 987
i.e. six digits are divisible by 987 & gives rem = 0
132/6 = 22 , (----22 times---,987987) will be divisible by 1001 & rem = 0 - 10 years agoHelpfull: Yes(82) No(4)
- rem = 0
987987987...(upto 132 digit) / 1001
987987 / 1001 = 987
i.e. six digits are divisible by 987 & gives rem = 0
132/6 = 22 , (987987)(----26 times) will be divisible by 1001 & rem = 0
- 10 years agoHelpfull: Yes(3) No(7)
- Answer will be 0.
Total no's of 6 digit number=22
now when we divide 987987/1001=0 - 10 years agoHelpfull: Yes(2) No(0)
- well Rakesh... when u r taking 6 digits then why 22 digits are giving remainder 0. Remainder should be 9879/1001=879.
- 10 years agoHelpfull: Yes(1) No(9)
- answer is zero.
- 10 years agoHelpfull: Yes(1) No(1)
- remainder = 0
987987987...(upto 132 digit) divided by 1001
987987 / 1001 = 987 and remainder = 0
i.e. six digits are divisible by 987 & gives remainder = 0
132/6 = 22 , (987987) 22 time will be divisible by 1001 & remainder = 0 - 10 years agoHelpfull: Yes(1) No(0)
- it will be 987
- 10 years agoHelpfull: Yes(0) No(2)
- 1 will be the ans
- 9 years agoHelpfull: Yes(0) No(1)
- opt mi Zero hai he ni even i got ans as 0
- 8 years agoHelpfull: Yes(0) No(0)
- its comibination of 987987 remainder 0 and 132is divisible by 6 means remainder is zero
- 8 years agoHelpfull: Yes(0) No(0)
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