Two typists of varying skills can do a typing job in 6 minutes if they work together. If the first typist typed alone for 4 minutes and then the second typist typed alone for 6 minutes, they would be left with 1/5 of the whole work. How many minutes would it take the slower typist to complete the typing job working alone?
(a) 10 minutes (b) 15 minutes (c) 12 minutes (d) 20 minutes

• (1/x+1/y)6=1
  1st typist worked alone for 4 min and 2nd alone for 6 min with 4/5th work completed i.e.
  4/x+6/y =4/5
  Solving both equations we get x=2/3y
  Substituting one of the eq we get x=10
  Y=15
• 9 years agoHelpfull: Yes(2) No(1)
• now think logically they both can complete the work in 6 minutes now the first typist typed alone 4 minutes and then the second typist typed alone for 6 minutes, it means if first typist work 2 more minutes after 4 minutes the work will be completed it means he can do 1/5th of work in 2 minutes so whole work in 5 * 2 = 10 minutes it means first can do the work alone in 10 minutes and together it is given in the question they complete the work in 6 minutes so you can easily calculate by basics of time & work that he will complete a work alone in 15 minutes. i.e. our answer that slower typist can complete the work in 15 minutes.
• 7 years agoHelpfull: Yes(2) No(0)
• ans 15
  if the first typist typed alone for 4 minutes and then the second typist typed alone for 6 minutes then he left 1/5 work means they 4/5 work complete n also b's work complete bcz he has worked 6 mins......... accrdng 2 ques
  then we find first typist work
  1/5 typing=2 day
  so whole typing=10 dys
  so second typing do=15 dys
• 9 years agoHelpfull: Yes(1) No(1)
• ans is 20 minutes
  explanation: let us consider the slower typist as 'A' who complets the work in 4 min so he does 3 min of work each day to complete the entire work. 1%5=4 where 5*4=20
• 4 years agoHelpfull: Yes(0) No(0)