varun throws two dice,and his score is sum of the values shown on dice,priya throws one dice and her score is square of value shown.what is the probability that priya score will be strictly more than varun's score??

• ans =3/6=1/2
  b/c priya score - 1,4,9,16,25,36
  varun can get maximum score=6,6=6+6=12
  3 value of priya score is greater then varun maxi score.so
  ans=3/6=1/2
• 10 years agoHelpfull: Yes(3) No(0)
• no o f possible sums on two dice= 1,2,3,4,5,6,7(i.e 1+6,2+5....),
  no. of possible sums on priya dice=1,4,9,16,25,36,49,64,81,10
  total cases=17,except 1 and 4 ,all cases are favourable for priya,so probability=15/17
• 10 years agoHelpfull: Yes(0) No(3)