Two people on cycle are traveling at 10 miles/hour in opposite direction. When they are at a distance of 50
miles, a housefly lands on the first cyclist and then flies to the other at a speed of 16 miles/hour. What is the
distance covered by fly?

• You can assume that when the fly lands on cyclist 1 they are 50 miles apart. The fly has to travel 50 + x
  miles at 16 miles/hour. Here x is the additional distance at 10 miles/hour. So the problem is now simplified as
  y = 50 + x (distance)
  (50 + x)/16 = x/10 (time)
  500 + 10x = 16x
  6x = 500
  x = 250/3 = 83.33
  y = 133.33
• 10 years agoHelpfull: Yes(1) No(0)
• when flie moves 16 mile in mean time other cyclist moves 10 mile
  therfore effective distance reduced =6 mile
  50-16+10=44
  44-16+10=38
  so similary subtracting the distance reduces to 0 mile
  as 8-16+10=2
  so distance covered= 16 *8(round of subtractions)+2=130 miles.
  
• 10 years agoHelpfull: Yes(0) No(0)
• Ans 40 miles
  
  The two cycles moving in opp direction
  Time taken is (50/20)=5/2 h
  Fly moves with speed of 16m/h
  
  Distance covered=16(5/2)
• 10 years agoHelpfull: Yes(0) No(0)
• total distance=50 m
  speed of cyclist + speed of fly=10+16=26 m/h
  time taken to cover 50 m = 50/26 h
  distance covered by the FLY= (50/26)*16=30.76m
• 10 years agoHelpfull: Yes(0) No(0)