a reduction of 20% in the price of orange enables a man to buy 5 more oranges for Rs 10.the price of an orange before reduction:

• P= PRICE OF 1 QUANTITY
  Q=NO. OF QUANTITY
  E= EXPENDITURE OR TOTAL PRICE
  let us assume that my total expenditure is 10Rs
  i.e p * q = 10 ............a
  now when the price decreases by 20% quantity increases by 5 for 10Rs which means 0.8p * (q+5)=10
  =>0.8pq + 4p = 10
  but pq=10 from a
  so =>0.8 * 10 +4p=10
  =>p=0.5
  hence original price of 1 orange is 0.5Rs.
• 10 years agoHelpfull: Yes(3) No(2)
• Let initially man buys Y number of oranges.
  So the price of 1 orange is Y/10=X...(1)
  Now when the price reduces,the man buys Y+5 oranges
  So the price of 1 orange becomes (Y+5)/10=0.8X...(2)
  Equating (1) and (2) and solving and neglecting - sign we get Y=25
  So initially,the price of 1 orange is 2.5
• 10 years agoHelpfull: Yes(1) No(1)
• the solution is 40p.
• 10 years agoHelpfull: Yes(0) No(3)
• price of 1 orange after reduction = 10/5 = 2
  let the price b4 reduction = x
  x - (20/100)*x = 2
  x= 2.5
• 10 years agoHelpfull: Yes(0) No(1)