how many different arrangement is possible for the word ARRANGE where two A,s never come together and two R's never come together

• total no of arrangements is 7!/(2!*2!)
  if they are together no .of ways is 5!
  7!/4-5!=1140
• 10 years agoHelpfull: Yes(2) No(2)
• total no of arrangements is 7!
  but when they are together then no of arrangements is 5!
  so 7!-5!=4920
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• 7!/(2!*2!) =1260
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• Total no of arrangements is 7!/(2!)^2
  now take both AA & RR together can be arranged in 4!(AARRANGE)
  Again AARR can be arranged themselve in 2!
  The answer is 7!/(2!)^2-(4!*2!)
• 10 years agoHelpfull: Yes(0) No(1)
• total no of ways= 7!/2!2!
  two A's two R's are occur together so club R's and A's then
  no of ways = 5!/2!2!
  two A's two R's are never occur together= 7!/2!2!-5!/2!2!=1230 ans...
• 10 years agoHelpfull: Yes(0) No(0)