CAT Exam Category

A and B can do a piece of work in 30 days.B and C can do a work in 24 days.C and A can do a work in 20 days.All work together for 10 days then B and C leave.how many days more will A to complete the work?

Read Solution (Total 3)

(A+B)'s 1 day work = 1/30
(B+C)'s 1 day work = 1/24
(A+C)'s 1 day work = 1/20
2(A+B+C) = 1/30 + 1/24 + 1/20
2*(A+B+C) = 1/8
(A+B+C)'s 1 day work = 1/16
(A+B+C)'s 10 days work = 10/16 = 5/8
Work left = 1 - 5/8 = 3/8
A's 1 day work = (A+B+C)'s 1 day work - (B+C)'s 1 day work
A's 1 day work = 1/16 - 1/24 => 1/48
A ll complete 1/48 part of work in ------ 1 day
A ll complete 3/8 part of work in ------ x days
x = (3*48)/8 = 18 days
So A ll complete the remaining work in 18 days

Ans : 18 days
9 years agoHelpfull: Yes(6) No(0)

18 will be the answer adding all three equation 2{1/a+1/b+1/c}=150/240=5/8
then add equation 1 and 3 we get 1/a+1/b=1/30 and 1/a+1/c=1/20 we get a=48 now remaning 3/8 work left will be done in 48*3/8 i.e 18
9 years agoHelpfull: Yes(0) No(0)
18 will be the answer adding all three equation 2{1/a+1/b+1/c}=150/240=5/8
then add equation 1 and 3 we get 1/a+1/b=1/30 and 1/a+1/c=1/20 we get a=48 now remaning 3/8 work left will be done in 48*3/8 i.e 18
9 years agoHelpfull: Yes(0) No(0)

CAT Other Question

9 litres are drawn from a cask full of water and filled with mik.9 litres of mixture are drawn and again filled with milk.now the quzntity of milk to that wzter in the cask is 16:9.how much mixture does the cask hold? A and B can do a piece of work in 12 days.B and C can do a work in 15 days.if A is twice as good a workman as C.find in what will B alone do it?