if any one has given accenture written xam plz share ur experience... plz send the placement papers of accenture at..

dimplekhushi922@gmail.com

• 1)
  n(E)=(n-2)!*2!
  n(s)=(n-1)! as circular arrngmnt
  now
  P(E)=(n-2)!*2!/(n-1)!
  =2/(n-1)
  P(E)'=(1-(2/n-1))=(n-3)/(n-1)
  now ATQ
  odd against:P(E)'/P(E)=(n-3)/2
  ans=(n-3)/2
  
  2)
  4 digit no's can be form in following ways=9*10*10*10
  only 1,3,7,9 can be multiplied to form 1,3,7,5 in end
  so favourable conditions = 4!
  p=(9*10*10*10-4!)/9*9*8*7
  
  3)
  double numbs are: 1,1 2,2 3,3 4,4 5,5 6,6. so total 6 types.
  now cases can be 4C2*(1*1/6 * 1*1/6 * 1*5/6 * 1*5/6) so ans is 25/216. rite?
  Alt. (6/36*6/36)
  
  4)
  chance of winning of b is.....5/6*1/6, 5/6*5/6*5/6*1/6.....
  p= 5/6*1/6 + 5/6*5/6*5/6*1/6 + 5/6*5/6*5/6*5/6*5/6*1/6 +..............
  p=1/6*5/6 [1+(5/6)^2+(5/6)^4+(5/6)^6.........)
  p=5/11
  
  
  5)
  
  chance of winning of b is..... 1/2*1/2 + 1/2*1/2*1/2*1/2 +...........
  p=1/3
  
  6)
  p'=(20C1*18C1*16C1*14C1)/(20C1*19C1*18C1*17C1)
  P=1-P'
  P=1-((20*18*16*14)/(20*19*18*17))
  
  7)2*(5c1(1/2)*4c1(1/2)*3c1(1/2)*2c1(1/2)*1c1(1/2))
  
  8)p=(4/5)^5
• 9 years agoHelpfull: Yes(0) No(0)