What is the probability that the chosen 4-digit number is a perfect square?

• Total 4-digit no's that are possible, 10000-1000 = 9000
  Perfect squares of 4-digit no. starts from 1024 which is the square of 32 and ends in 9801 which is the square of 99...
  So No. of 4-digit numbers which are perfect squares are 99-31 = 68
  Prob. will be = 68/9000 = 0.00755 = 0.0076
• 10 years agoHelpfull: Yes(22) No(0)
• The total number of different 4 digit number is=9*10*10*10=9000
  And the first four digit number which is perfect square=1024=(32)^2
  and last four digit number which is perfect square=9801=(99)^2
  
  So,the total number of four digit number which is perfect square=99-32+1=68
  
  So,the probability that the chosen 4-digit number is a perfect square=(68/9000)=0.0075
• 10 years agoHelpfull: Yes(7) No(0)
• total four digit number = 9999-1000 = 8999
  total two digit number whose square is a four digit number = 99 - 32 = 67
  probability of choosing perfect square = 67/8999 = 0.007445
• 10 years agoHelpfull: Yes(0) No(0)
• Ans: 17/2250
  Sol:
  As there are 9000 no's that have 4 digit staring from 1000 -9999
  in between these sqaures of no's staring from 32 -99 i.e a total of 68 no's have their squares as a 4 digit no....
  as, (32)^2= 1024
  (33)^2=1089....so on...(99)^2=9801..
  Hence reqired probability =68/9000 i.e 17/2250
• 10 years agoHelpfull: Yes(0) No(1)
• 4digit no. which are perfect square are from the square of no.32 to 99. so no.of total such no=99-32+1=68
  totalno 0f 4 digit no =9000
  p=68/9000
• 10 years agoHelpfull: Yes(0) No(0)