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Maths Puzzle
Numerical Ability
The cost of 20 pens,22 erasers and 25 sharpeners is Rs.196. The cost of 23 pens, 27 erasers and 30 sharpeners is Rs.233. If the cost of 109 pens, 125 erasers and 140 sharpeners is Rs.k, what is the value of K?
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- since, 20 pens, 22 erasers and 25 sharpeners cost Rs.196
hence, 40 pens, 44 erasers and 50 sharpeners cost Rs.392
again,
since, 23 pens, 27 erasers and 30 sharpeners cost Rs.233
hence, 69 pens, 81 erasers and 90 sharpeners cost Rs.699
hence, total of (40+69=109)pens, (44+81=125)erasers and(50+90=140)sharpeners will cost Rs.(392+699=1091). - 10 years agoHelpfull: Yes(4) No(0)
- k=1091
for pens : ((20+23)*3)-20) = 109
similarly for erasers and sharpners
i.e. ((22+27)*3)-22 = 125 and ((25+30)*3)-25)
so k = ((196 + 233)*3)-196 = 1091 - 10 years agoHelpfull: Yes(0) No(0)
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