a man travels from X to Y at a average speed of 6m/hr and from Y to Z at 12m/hr.what is the average speed?

• Can't be determined...because in question it is not specified the distance between X to Y and Y to Z is.If the distance is equal then the average speed will be=2*6*12(6+12)=8km/hr
• 10 years agoHelpfull: Yes(4) No(2)
• Avg speed=2xy/(x+y)
  So, (2×6×12)/(6+12)
  =8 km/hr
• 10 years agoHelpfull: Yes(3) No(0)
• here we have one formula 2xy/(x+y)so,
  if we apply that formula we will get 8 m/hr.
  2*6*12/(6+12)=8
• 10 years agoHelpfull: Yes(1) No(0)
• avg speed=total dist/total time
  let there be 12km(lcm of 6 and 12) distance eachfrom x to y and y to z
  
  so avg speed =24/{(12/6)+(12/12)}=8kmph
• 10 years agoHelpfull: Yes(0) No(0)
• 1600
  is ans
• 10 years agoHelpfull: Yes(0) No(1)
• 4
  6*12/(6+12)=4
• 10 years agoHelpfull: Yes(0) No(0)