9. A square ABCD shares it 25% of area with a rectangle AEFG and rectangle share its 50% of its area with square. AB < AE and AD > AG. Find AE/AG.

• according to the question
  if x is the side of square and a and b are the sides of rectangle
  
  then x^2 = 2(a*b) -------eq.1
  
  since the rectangle share its 50% area ..so the length of the rectangle should be double to the side of the square
  here, AE > AB
  so, AE = 2x = a
  
  
  and since the square share 25% of its area with rectangle, so its side should be 4 times the breadth of the rectangle
  here, AD > AG
  so, AG = x/4 = b
  
  and a and b are satisfying eq.1 also
  
  hence AE/AG = 2x/(x/4)= 8
  
  it can be better understood after drawing the square and rectangle on paper with their shared areas
• 10 years agoHelpfull: Yes(10) No(1)
• after visualizing the diagram
  AE is collinear with AB
  AG collinear with AD
  
  let side of square is 4x, AB=4x
  as 25% of area of square= 50% area of rectangle
  
  AG = 14 AD
  AG = x
  AE = 2 AB
  AE= 2x
  AE/AG = 8x/x = 8/1
• 10 years agoHelpfull: Yes(6) No(0)
• square ABCD
  rectangle AEFG(AB
• 10 years agoHelpfull: Yes(0) No(0)