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There is 17 friends (A1,A2,A3....A17).If A1 have to have shake with all with out repeat. How many hand shakes possible?
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- 16. doing handshake with the remaining 16 people
- 13 years agoHelpfull: Yes(11) No(2)
- 16 hand shakes
- 13 years agoHelpfull: Yes(7) No(2)
- 136
A1 have 16 shakes
A2 have 15 shakes
A3 have 14 shakes
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A15 have 2 shakes
a16 have 1 shakes
so total is 1+2+3+...+16=16(16+1)/2=136 - 13 years agoHelpfull: Yes(6) No(10)
- go easy without rep....n-1=17-1=16 iz ans
- 13 years agoHelpfull: Yes(6) No(0)
- a1 has to handsake with oter 16,similarly a2 has to handsake with from a3 to a17(dont make handsake with a1 and a2,since no repetation is allowed),similarly a3 handsake with rest a4 to a17; so finally we have (16+15+14+......+3+2+1)=136;
using A.P formula-n*(n-1)/2;here n=16; - 13 years agoHelpfull: Yes(3) No(1)
- n*(n+1)/2;n=16
ans is 136. - 13 years agoHelpfull: Yes(2) No(2)
- ans should be 136.
as (16+15+14+......+3+2+1)=136 - 13 years agoHelpfull: Yes(1) No(2)
- 17*16=272 shake hands are possible
- 13 years agoHelpfull: Yes(0) No(8)
- 17*16=272 shakehands
- 13 years agoHelpfull: Yes(0) No(7)
- a1 shakes with 16 people and 16 people shake with a1 32
- 13 years agoHelpfull: Yes(0) No(2)
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