C++
Programming and Technical
Programming
Database
class UseStatic {
static int a = 10;
static int b;
static void meth(int x) {
System.out.println("x = " + x);
System.out.println("a = " + a);
System.out.println("b = " + b);
}
public static void main(String args[]) {
UseStatic.meth(42);
}
static {
System.out.println("I am M4Math Geek");
b = a * 4;
}
}
Read Solution (Total 2)
-
- I am M$Math Geek
x=42
a=10
b=40 - 10 years agoHelpfull: Yes(6) No(0)
- As soon as the UseStatic class is loaded, all of the static statements are run.First, a is set to 3, then the static block executes(printing a message),and finally, b is initialized to a* 4 or 12.Then main( ) is called,which calls meth( ), passing 42 to x. The three println( ) statements refer to the two static variables a and b,as well as to the local varible x.
Here is the output of the program:
Static block initialized.
x = 42
a = 3
b = 12 - 10 years agoHelpfull: Yes(1) No(8)
C++ Other Question
What I wanted to do here is to develop, in less than a page of code, a toy spelling corrector that achieves 80 or 90% accuracy at a processing speed of at least 10 words per second.
So here, in 21 lines of Python 2.5 code, is the complete spelling corrector:
import re, collections
def words(text): return re.findall('[a-z]+', text.lower())
def train(features):
model = collections.defaultdict(lambda: 1)
for f in features:
model[f] += 1
return model
NWORDS = train(words(file('big.txt').read()))
alphabet = 'abcdefghijklmnopqrstuvwxyz'
def edits1(word):
splits = [(word[:i], word[i:]) for i in range(len(word) + 1)]
deletes = [a + b[1:] for a, b in splits if b]
transposes = [a + b[1] + b[0] + b[2:] for a, b in splits if len(b)>1]
replaces = [a + c + b[1:] for a, b in splits for c in alphabet if b]
inserts = [a + c + b for a, b in splits for c in alphabet]
return set(deletes + transposes + replaces + inserts)
def known_edits2(word):
return set(e2 for e1 in edits1(word) for e2 in edits1(e1) if e2 in NWORDS)
def known(words): return set(w for w in words if w in NWORDS)
def correct(word):
candidates = known([word]) or known(edits1(word)) or known_edits2(word) or [word]
return max(candidates, key=NWORDS.get)
The code defines the function correct, which takes a word as input and returns a likely correction of that word. For example:
>>> correct('speling')
'spelling'
>>> correct('korrecter')
'corrector'
Give the output of following program segment with explanation.
main()
{int a=32, *x=&a;
char ch=65, &e=ch;
e+=a;
*x+=ch;
cout<