lcm of two no is 630 and their hcf is 9.if sum of no is 153 then ratio of two no is
options
a)70
b)9
c)0.7
d)10/7
e)c or d

• e) c or d
  
  if two numbers are x,y then
  LCM(x,y)*HCF(x,y)= x*y
  => 630*9 = xy ------------(1)
  
  given, x+y = 153 -----(2)
  from (1)&(2)
  x(153-x)=630*9
  => x^2 -153x + 90*63 = 0
  => (x-63)(x-90)=0
  => x = 63,90
  (x,y)=(63,90)or(90,63)
  ratio = 63/90 = .7 or 90/63 = 10/7
  
• 9 years agoHelpfull: Yes(5) No(0)
• let the nos. be x and y
  lcm*hcf=x*y
  
  630 * 9 = x*y
  x*y = 5670
  
  x+y = 153
  
  but let us check in options...since most of the options have 10 and 7 so let us take 10 and 7
  
  the hcf is 9..we will multiply 9 by 10 and 9 by 7
  we will get
  
  90 and 63 and these values are satisfying the equations so
  
  x=63
  y=90
  
  or we can also solve the equations by substitution method ;)
• 9 years agoHelpfull: Yes(0) No(1)
• the nos. will ne 90 & 63
  lcm=630,hcf=9,sum=153
  so ratio is either 10/7 or 7/10
  c or d
• 9 years agoHelpfull: Yes(0) No(0)