Two friends A and B working together completed a work in 26 days. Their skills of doing the work are in the ratio 8:5. How many days will B take, if engaged alone?
(a) 10 days
(b) 16 days
(c) 12 days
(d) 18 days

• a:b:8:5
  as we want B
  (5/13)*26=10
  option a
• 10 years agoHelpfull: Yes(3) No(2)
• how b alone can in 10 days. In 26 days b's work is 10 days. b alone means it will take more days.
  8y+5y=1/26, 13y=1/26, y=1/338.
  Now B's work is 1/338 *5. so B alone can do the same work in 67 5/3 days or 67.6 days.
• 9 years agoHelpfull: Yes(3) No(2)
• each can do work in 8x and 5x
  now both can do the work in 26 dyas
  therefore
  8x+5x=26
  x=2
  so A can do the work in 16 days and B can do the work in 10 days
• 9 years agoHelpfull: Yes(2) No(1)
• efficiency*days=total work
  13*26=338 total work
  so B can alone do the work is 338/5=67.6 days
• 4 years agoHelpfull: Yes(2) No(0)
• both can do in 26 days..
  but only B can do in (5/13)*26 days..
  so 10 days..
  thats it..
• 10 years agoHelpfull: Yes(1) No(1)
• How B can work in 10 days...because when A+B takes 26 days then how is this possible to B take less than 26.....please explain....
• 4 years agoHelpfull: Yes(0) No(0)