3 couples and one child of each of the three couples are to be seated in a row such that the child is sitting between the parents. In how many ways can the 9 people be seated?
Choose one answer.
a. 18
b. 24
c. 36
d. 48

• no of ways for one couple will be 2!
  no of ways for 3 couple- 2!*3
  then consider each couple a unit then arrange them
  so number of ways of arranging couples will be 3!=6
  so total no of ways = 6*2*3=36
  
  its 24
• 10 years agoHelpfull: Yes(1) No(0)
• pcp pcp pcp is formation
  in which 3 pairs can be arranged in 3! ways ie 6
  parents can arrange themselves in each group in 2! ways=2
  for 3 pairs its 6 ways
  so total ways is 6*6=36
  
• 10 years agoHelpfull: Yes(0) No(0)