. The in centre of a triangle with vertices A(1,√3) B(0,0) and C(2,0) is

• ans: (1,1/√3)
  
  let the centr= O(h,k)
  so the distance of the center fron each vertices will be same..i.e AO=BO=CO
  we know distnce=root undr (x1-x2)^2+(y1-y2)^2
  AO=root undr (h-1)^2+(k-root undr 3)^2....(1)
  similarly determine BO and CO
  then equating eq (1) & (2) we get 2√3+2h=4
  equating eq (1) & (3) we get 2√3-2h=0
  from this two we can find (h,k) which is (1,1/√3)...
  plz chk it nd inform if thr is ny error
  
• 10 years agoHelpfull: Yes(0) No(1)